The concept used to settle this problem is based on molecular orbit diagram.

You are watching: Construct the molecular orbital diagram for h2 and then identify the bond order

A molecular orbital diagram is used to define chemical bonding in a molecule. This chart is based ~ above the molecular orbital theory.

According to the molecular orbital theory, molecule orbitals the a molecule is created by combination of its atomic orbitals and electrons room distributed among the molecule orbitals.

The shortcut order of any type of molecule is calculated by utilizing electrons i m sorry are dispersed in molecular orbital diagram.

BO=12(nb−na)B_O\rm = \frac12\left( n_\rmb - n_\rma \right)BO=21(nb−na) …… (1)

Here, BOB_OBO is link order, nbn_\rmbnb is total variety of electrons existing in bonding orbital and nan_\rmana is total variety of electrons current in antibonding orbital.

**(1)**

Construct molecular orbital diagram and also fill 333 electrons in bonding and antibonding 1s1\rms1s orbitals.

**(2)**

Total number of electrons in bonding orbitals is 222 .

Total number of electrons in antibonding orbit is 111 .

The formula for calculating link order is together follow.

BO=12(nb−na)B_O\rm = \frac12\left( n_\rmb - n_\rma \right)BO=21(nb−na)

Substitute 222 for nbn_\rmbnb and 111 because that nan_\rmana in the equation (1) to calculate the bond order.

BO=12(2−1)=0.5\beginarrayc\\B_O = \frac12\left( 2 - 1 \right)\\\\ = 0.5\\\endarrayBO=21(2−1)=0.5

Bond order because that H2−\rmH_2^ - H2− is 0.50.50.5 .

Ans: part 1The molecular orbit diagram that H2−\rmH_2^ - H2− is displayed as follows:

Part 2The link order for H2−\rmH_2^ - H2− is 0.50.50.5 .

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